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Question

int i = 4;
string text = "Player ";
cout << (text + i);

I'd like it to print Player 4.

The above is obviously wrong but it shows what I'm trying to do here. Is there an easy way to do this or do I have to start adding new includes?

Answer

Your example seems to indicate that you would like to display the a string followed by an integer, in which case:

string text = "Player: ";
int i = 4;
cout << text << i << endl;

would work fine.

But, if you're going to be storing the string places or passing it around, and doing this frequently, you may benefit from overloading the addition operator. I demonstrate this below:

#include <sstream>
#include <iostream>
using namespace std;
std::string operator+(std::string const &a, int b) {
  std::ostringstream oss;
  oss << a << b;
  return oss.str();
}
int main() {
  int i = 4;
  string text = "Player: ";
  cout << (text + i) << endl;
}

In fact, you can use templates to make this approach more powerful:

template <class T>
std::string operator+(std::string const &a, const T &b){
  std::ostringstream oss;
  oss << a << b;
  return oss.str();
}

Now, as long as object b has a defined stream output, you can append it to your string (or, at least, a copy thereof).